When SO2 is passed through a solution of K2Cr2O7 turns green. The change in oxidation state of chromium and sulphur are ___________________ respectively.
A
+3 to +6 and +4 to +2
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B
+6 to +3 and +4 to +6
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C
+4 to +6 and +4 to -2
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D
no change in 0 states
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Solution
The correct option is B +6 to +3 and +4 to +6 K2Cr2O7+SO2+H2SO4→K2SO4+Cr2(SO4)3+H2O Oxidation number of Cr in K2Cr2O7 is +6 and in Cr2(SO4)3 is +3. Oxidation number of S in SO2 is +4 and in (SO4)2− ion is +6.