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Calculating Oxidation Number

When SO2 is...

Question

When ${S O}_{2}$ is passed through acidic solution of potassium dichromate, then chromium sulphate is formed. Change in valency of chromium is

A

+ 4

to

+ 2

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B

+ 5

to

+ 3

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C

+ 6

to

+ 3

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D

+ 7

to

+ 2

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Solution

The correct option is C $+ 6$ to $+ 3$
In this reaction chromium change from $+ 6$ to $+ 3$ oxidation state.

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Similar questions

Q. Write the net ionic equation for the reaction of potassium dichromate

(V I)

K_{2} {C r}_{2} O_{7}

with sodium sulphite,

{N a}_{2} {S O}_{3}

in an acid solution to give chromium

(I I I)

ion and the sulphate ion.

Q. When sulphur dioxide gas is passed through acidified potassium dichromate solution, the colour of the solution changes from :
(1) orange to yellow
(2) orange to green
(3) green to orange
(4) yellow to green

S O_{2}

is passed through an acidic solution of potassium dichromate, chromium sulphate is formed. The change in oxidation number of chromium is:

S O_{2}

is passed through an acidic solution of potassium dichromate, chromium sulphate is formed. The change in oxidation number of chromium is:

S O_{2}

is passed through acidified solution of potassium dichromate, then chromium sulphate is formed. The change in oxidation number of chromium is?

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