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Standard XII

Chemistry

Oxides of Sulphur

When SO2 is...

Question

When $S O_{2}$ is passed through cupric chloride solution:

blue precipitate is obtained

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solution becomes colourless,no ppt is obtained.

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solution becomes colourless and white ppt is obtained.

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Solution

The correct option is D solution becomes colourless and white ppt is obtained.
When $S O_{2}$ is passed through cupric chloride solution solution becomes colourless and white ppt is obtained due to the formation of acidic cuprous chloride ( $C u C l$ ).
$C u C l_{2} + 2 H_{2} O + S O_{2} \to 2 C u C l + 2 H C l + H_{2} S O_{4}$
Hence option C is correct,

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Similar questions

Q. The following are two reaction schemes involving Mg.

Scheme-I : Mg

a i r Δ \to

colourless solid A

H C l \to

colourless soltuion B

N a_{2} C O_{3} \to

white ppt C

Δ \to

D colourless gas E

C a (O H)_{2} \to

white ppt F

Scheme-II : Mg

d i l . H_{2} S O_{4} \to

colourless solution G

N a O H \to

white ppt H

H N O_{3} \to

colourless solution

e v a p o r a t e \to

Δ \to

J gas +

O_{2} + D

Find I.

Q. Colourless salt (A) give white ppt (B) with NaOH; ppt (B) dissolves in excess of NaOH to form (C). On passing

H_{2} S

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A g N O_{3}

solution. What is (A)?

Q. You are given a colourless solution and was told to add a little

N a C l

solution to it. A cloudy white precipitate was made. What conclusion should you draw about the nature of the colourless solution? The ppt dissolves in hot water, then the ppt is :

Q. To a solution containing

C a^{2 +}, A g^{+} C u^{2 +}

and

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(A)

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is passed through the filtrate, a black ppt.

(B)

is formed. On removing

(B)

by filtration, it gave a white ppt.

(C)

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N a_{2} C O_{3}

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Q. An aqueous solution of colourless metal sulphate

M

, gives a white ppt. with

N H_{4} O H

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. On passing

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When SO2 is passed through cupric chloride solution:

The correct option is D solution becomes colourless and white ppt is obtained.When SO2 is passed through cupric chloride solution solution becomes colourless and white ppt is obtained due to the formation of acidic cuprous chloride (CuCl).CuCl2+2H2O+SO2→2CuCl+2HCl+H2SO4Hence option C is correct,

When $S O_{2}$ is passed through cupric chloride solution: