When SO₂ is passed through acidified K₂Cr₂O₇ solution.
(a) The solution turns green
(b) The solution is decolourized
(c) Reduction of SO₂ takes place
(d) Green ppt of Cr₂(SO₄)₃ is formed

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Solution

(a) the solution turns green

When SO₂ is passed through acidified K₂Cr₂O₇ solution, the solution turns green. This is because the ${Cr}_{2} O_{7}^{2 -}$ ion is reduced to the Cr³⁺ ion, which is green in colour.

K₂Cr₂O₇+ 3SO₂+ H₂SO₄→ K₂SO₄ + 2Cr³⁺(aq.) + 3 ${SO}_{4}^{2 -}$ (aq.) + H₂O

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