When sodium propionate is heated with soda lime, the product formed is

Methane

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Ethane

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Ethene

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Ethyne

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Solution

The correct option is B Ethane
When sodium propionate is heated with soda lime, the product formed is ethane and sodium carbonate.

The reaction is as follows:
$C_{2} H_{5} C O O N a + N a O H \to C_{2} H_{6} + N a_{2} C O_{3}$

The reaction follows with the removal of $C O_{2}$ from a carboxylic acid is called decarboxylation reaction.
Hence the correct option is 'B'

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Similar questions

1)- Give a chemical test to distinguish between: Ethene gas and Ethane gas.

2)- Identify the gas evolved when: Sodium propionate is heated with soda lime.

What happens when sodium ethanoate is heated with soda lime?

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