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Nitric Acid

When solution...

Question

When solution of $Z n S$ in $d i l . H C l$ is treated with $N a O H$ solution, a white ppt. is formed which dissolves in excess of $N a O H$ due to formation of :

Z n C l_{2}

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Z n (O H) C l

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N a_{2} Z n O_{2}

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None of these

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Solution

The correct option is C $N a_{2} Z n O_{2}$
Option (C) is correct.
When solution of $Z n S$ in $d i l . H C l$ is treated with $N a O H$ solution, a white ppt. is formed which dissolves in excess of $N a O H$ due to formation of $N a_{2} Z n O_{2}$ .
$Z n S + 2 H C l ⟶ Z n C l_{2} + H_{2} S$
$Z n C l_{2} + 2 N a O H ⟶ Z n {(O H)}_{2} + 2 N a C l$
$\begin{matrix} Z n {(O H)}_{2} + 2 N a O H & ⟶ N a_{2} Z n O_{2} & + & 2 H_{2} O (s o l u b l e) \end{matrix}$

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