When some potential difference is maintained between A and B, current I enters the network at A and leaves at B. Find i) the current flowing between C and D. ii) the equivalent resistance between A and B.
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Solution
i) As C and D are joined by a connecting wire, they are at the same potential and no current will flow between C and D. ii) Req = (20 || 5) + (20 || 5) = 4 + 4 = 8 ohms