Question

When source and detector are stationary but the wind is blowing at speed , the apparent wavelength ${\lambda }^{\prime }$ on the wind side is related to actual wavelength $\lambda$ by [take speed of sound in air as v]

• A.
• B.
• C.
• D.

Answer 1

The correct option is C

${\lambda }^{\prime }=\frac{Wavespeedrelativetolistener}{f}\Rightarrow {\lambda }^{\prime }=\frac{v+v_{\omega }}{f}=\frac{v+v_{\omega }}{f}\lambda$