When sulphur is boiled with $N a_{2} S O_{4}$ solution, the compound formed is:

Sodium sulphide

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Sodium sulphate

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Sodium persulphate

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Sodium thiosulphate

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Solution

The correct option is C Sodium thiosulphate

When sodium sulfate ( $N a_{2} S O_{4}$ ) reacts with $S$ it forms sodium thiosulfate( $N a_{2} S_{2} O_{4} (s)$ ).
$N a_{2} S O_{4} (s) + S (s) \to N a_{2} S_{2} O_{4} (s)$
Hence option D is correct.

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