When sulphur is reacted with ozone in water,the product formed is:

H_{2} S

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H_{2} S O_{3}

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H_{2} S O_{4}

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H_{2} S_{2} O_{8}

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Solution

The correct option is C $H_{2} S O_{4}$
$2 S + 2 O_{3} + 2 H_{2} O ⟶ 2 H_{2} S O_{4}$
$H_{2} S O_{4}$ is formed when $S, O_{3}$ and $H_{2} O$ reacts.

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Similar questions

When sulphur trioxide gas is dissolved in $H_{2} S O_{4}$ , the product obtained is

M g + H_{2} S O_{4} \to M g S O_{4} + H_{2}

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