Question

Question 115.
When Sunita weighed herself on Monday, she found that she had gained 1$\frac{1}{4}$ kg. Earlier her weight was 46$\frac{3}{8}$ kg. What was her weight on Monday?

Answer 1

Given that

Sunita's weight earlier = 46$\frac{3}{8}$ kg

Weight gained by Sunita(when she weighed on Monday) = 1$\frac{1}{4}$ kg

Sunita's weight earlier + Weight gained = Sunita's weight on Monday

On rearranging the equation we get:

Sunita's weight on Monday = Sunita's weight earlier + Weight gained

On substituting the values we get:

Sunita's weight on Monday = 46$\frac{3}{8}$ + 1$\frac{1}{4}$ kg

We can express a mixed fraction as an improper fraction as $\frac{(\text{Whole}\times \text{Denominator})\text{+ Numerator}}{\text{Denominator}}$.

$\therefore$ Sunita's weight on Monday = 46$\frac{3}{8}$ + 1$\frac{1}{4}$ kg = $\frac{46\times 8+3}{8}+\frac{1\times 4+1}{4}=\frac{368+3}{8}+\frac{4+1}{4}=\frac{371}{8}+\frac{5}{4}$ kg

Now, the LCM of 8 and 4 is 8.

$\therefore$ Sunita's weight on Monday = $\frac{371}{8}+\frac{5}{4}=\frac{371\times 1+5\times 2}{8}=\frac{371+10}{8}=\frac{381}{8}$ kg

We can express an improper fraction as a mixed fraction by dividing the numerator by denominator to obtain the quotient and the remainder.

Then the mixed fraction will be written as $\text{Quotient}\frac{\text{Remainder}}{\text{Divisor}}$.

$\therefore$ Sunita's weight on Monday = $\frac{381}{8}=47\frac{5}{8}$ kg

Hence, the weight of Sunila on Monday was $47\frac{5}{8}kg.$