When sunlight is incident on water surface at glancing angle of $37^{o}$ , the reflected light is found to be completely plane-polarised. The refractive index of water is

4 / 3

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3 / 4

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3 / 2

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2 / 3

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Solution

The correct option is B $3 / 4$
$\begin{matrix} G i v e n : - i = 37^{\circ} Brewster's law tan i = μ tan 37 = μ \frac{3}{4} = μ 0.75 = μ \end{matrix}$

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When sunlight is incident on water surface at glancing angle of 37o, the reflected light is found to be completely plane-polarised. The refractive index of water is

The correct option is B 3/4Given:−i=37∘ Brewster's law tani=μtan37=μ34=μ0.75=μ

When sunlight is incident on water surface at glancing angle of $37^{o}$ , the reflected light is found to be completely plane-polarised. The refractive index of water is

The correct option is B $3 / 4$
$\begin{matrix} G i v e n : - i = 37^{\circ} Brewster's law tan i = μ tan 37 = μ \frac{3}{4} = μ 0.75 = μ \end{matrix}$