Question

When system de-excites from its excited state to ground state, the wavelength of radiation is

• A. $1217\mathring{A}$
• B. $2431\mathring{A}$
• C. $608\mathring{A}$
• D. None of these

Answer 1

The correct option is B $2431\mathring{A}$

Given, system de-excites from its excited state to ground state.
Therefore, $n_1=1and{n}_2=2$
$\frac{1}{\lambda }=\left(\frac{1.097\times {10}^7}{2}\right)(1-\frac{1}{4})\Rightarrow \lambda =2.43\times {10}^{-7}m=2430\mathring{A}$