When temperature is increased by $1^{o} C$ , velocity of sound in air increases by

0.61 m s^{- 1}

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6.1 m s^{- 1}

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61 m s^{- 1}

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610 m s^{- 1}

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Solution

The correct option is B $0.61 m s^{- 1}$
Velocity of sound in air $v \propto \sqrt{T}$
$⟹$ $\frac{v^{'}}{v} = \sqrt{\frac{T^{'}}{T}}$
Let the initial temperature $T = 273 K$
Speed of sound in air at $273 K$ $v = 330 m / s$
New temperature $T^{'} = 273 + 1 = 274 K$
$∴ \frac{v^{'}}{330} = \sqrt{\frac{274}{273}}$
$⟹$ $v^{'} = 330.61 m / s$
Thus increase in sound $Δ v = v^{'} - v = 330.61 - 330 = 0.61 m / s$

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