When tert-butylchloride is added to an equal amount of ethanol in an inert solvent, one of the products is ethyl tert-butyl ether. When the concentration of tert-butyl chloride is doubled, the rate of the reaction:

drops alarmingly to a small fraction

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doubles

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remains constant

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halves

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Solution

The correct option is B
doubles

This reaction of clearly $S_{N} 1$ . The rate expression is:

$R e a c t i o n r a t e = [t e r t - b u t y l c h l o r i d e]$

Since the rate is only dependant on the concentration of tert-butyl chloride, the rate doubles with the doubling of the concentration of tert-butyl chloride.

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Q. When tert-butylchloride is added to an equal amount of ethanol in an inert solvent, one of the products is ethyl tert-butyl ether. When the concentration of ethanol is doubled, the rate of the reaction:

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When tert-butylchloride is added to an equal amount of ethanol in an inert solvent, one of the products is ethyl tert-butyl ether. When the concentration of tert-butyl chloride is doubled, the rate of the reaction:

The correct option is B doubles This reaction of clearly SN1. The rate expression is: Reaction rate=[tert−butylchloride] Since the rate is only dependant on the concentration of tert-butyl chloride, the rate doubles with the doubling of the concentration of tert-butyl chloride.