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Electrolysis of Aqueous Sodium Chloride

When the aque...

Question

When the aqueous solution of $L i_{2} S O_{4}$ electrolyzed the products formed at cathode and anode respectively are

Li and $S_{2} O_{8}$

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$H_{2}$ (gas) and $O_{2}$ (gas)

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Li and $O_{2}$ (gas)

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$H_{2}$ (gas) and $S_{2} O_{8}$

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Solution

The correct option is B
$H_{2}$ (gas) and $O_{2}$ (gas)

Reduction potential of water > Reduction potential of Li. So, at cathode water gets reduced to give hydrogen gas.

Similarly, oxidation potential of water < oxidation potential of sulphate ions.

So, at anode water gets oxidized to give oxygen.

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Similar questions

Aqueous $C u S O_{4}$ is electrolyzed using $A g$ as anode and $C u$ as cathode, then product of electrolysis at anode and cathode are, respectively

N a O H, 4 g

O_{2}

H_{2}

0.224 L

H_{2}

O_{2}

H_{2}

O_{2}

H_{2}

O_{2}

67.2 litres

H_{2}

S T P

C u

C u (I I)

C u

H_{2} + 2 O H^{-} \to 2 H_{2} O + 2 e^{-}

O_{2} + 2 H_{2} O + 4 e^{-} \to 4 O H^{-}

H_{2} S_{2} O_{8}

O_{2}

9.72 L

H_{2}

2.35 L O_{2}

H_{2} S_{2} O_{8}

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