When the beam of light travels in a medium with lesser velocity than that of in vaccum then the value of wavelength and frequency will respectively

Increase, decrease

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Increase, unchanged

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Decrease, unchanged

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Decrease, decrease

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Solution

The correct option is D Decrease, unchanged
Energy $= \frac{4 c}{λ} = 4 ν$ which is constant.
Here, velocity is decreasing so, to make constant energy $λ$ should also decrease and frequency remains constant.

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