Question

When the bulb of a constant volume hydrogen thermometer is placed in melting ice, the pressure recorded is $80cmHg$ and when immersed is boiling water, it is $113cmHg$. When the bulb is placed in another boiling liquid, the pressure recorded is $143cmHg$.What is the boiling point of the liquid?

Answer 1

In constant hydrogen gas thermometer

t=$\left(\frac{p_t-p_0}{p_{100}-p_0}\right)\times {100}^{0}C$

$=\left(\frac{143-80}{113-80}\right)\times {100}^{0}C$

$=\frac{63}{33}\times 100$

$\cong 200°C$