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Question

When the concentration of a reactant in reaction AB is increased by 8 times but rate increases only 2 times, the order of the reaction would be 1/n.
value of n is ?

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Solution

r1=k[A]n
r2=2r1=k[8A]n
2r1r1=(8)n
(2)1=(2)3n
3n=1
n=13

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