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Question

When the concentration of alkyl halide is triple and concentration of OH− is reduced to half, the rate of SN2 reaction is increased by :
(correct answer +2, wrong answer -0.5)

A
3 times
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B
1.5 times
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C
2 times
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D
6 times
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Solution

The correct option is B 1.5 times
As reaction is going via SN2 pathway, means that the reaction rate is dependent on concentration of both substrate and OH. Hence, reaction rate can be written as :
R1=k[Substrate][OH]...(i)
If the concentration of alkyl halide i.e., substrate is tripled and that of [OH] is halved. The reaction rate changes as :
R2=k[3×substrate][OH2]...(ii)
On dividing (i) and (ii) , we get
R2R1=32=1.5 times

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