When the concentration of alkyl halide is triple and concentration of OH− is reduced to half, the rate of SN2 reaction is increased by : (correct answer +2, wrong answer -0.5)
A
3times
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B
1.5times
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C
2times
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D
6times
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Solution
The correct option is B1.5times As reaction is going via SN2 pathway, means that the reaction rate is dependent on concentration of both substrate and OH−. Hence, reaction rate can be written as : R1=k[Substrate][OH−]...(i) If the concentration of alkyl halide i.e., substrate is tripled and that of [OH−] is halved. The reaction rate changes as : R2=k[3×substrate][OH−2]...(ii) On dividing (i) and (ii) , we get R2R1=32=1.5times