When the current in a conductor is doubled, keeping its resistance constant, the heat generated in the conductor will be:

double of the original

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4 times of the original

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3 times of the original

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8 times of the original

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Solution

The correct option is B
4 times of the original

We know heat produced in a conductor is $H = I^{2} R t$ , where ' $I$ ' is the current flowing, ' $R$ ' is the resistance of wire and ' $t$ ' is the time for which current is flowing in a conductor.

When electrical resistance ' $R$ ' and time period ' $t$ ' is kept constant then, $H \propto I^{2}$ .
So, if the current is doubled, the heating effect of a current through a conductor becomes 4 times of the original.

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