Question

When the current in a conductor is doubled, keeping other parameters constant, the heat generated in it will become ___ times.

Answer 1

We know that, $H=i^{2}Rt$

When current is doubbled, $H^{\prime }$ = ${i^{\prime }}^{2}Rt=(2i{)}^{2}Rt=4i^{2}Rt=4H$

So, the heat generated becomes 4 times of the original value.