Question

When the displacement is half the amplitude, the ratio of potential energy to the total energy is

• A.
• B.
• C. 1
• D.

Answer 1

The correct option is B

$\frac{U}{E}=\frac{\frac{1}{2}m{\omega }^2{y}^2}{\frac{1}{2}m{\omega }^2{a}^2}=\frac{y^2}{a^2}=\frac{{\left(\frac{a}{2}\right)}^2}{a}=\frac{1}{4}$