When the equation $y = 5 x - 12$ is written in the standard form, the value of $c^{2}$ will be.

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Solution

Given equation: $y = 5 x - 12$
Also, $y = 5 x - 12$ can be written as $5 x - y - 12 = 0$
So, on compairing $5 x - y - 12 = 0$ to the standard form ax + by + c = 0 we get,
a = 5
b = -1
c = -12
Now,
$c^{2}$ = $(- 12)^{2}$
$c^{2}$ = 144
Therefore, value of $c^{2}$ is 144.

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When the equation y=5x−12 is written in the standard form, the value of c2 will be.

Given equation: y=5x−12 Also, y=5x−12 can be written as 5x−y−12=0 So, on compairing 5x−y−12=0 to the standard form ax + by + c = 0 we get, a = 5 b = -1 c = -12 Now, c2 = (−12)2 c2 = 144 Therefore, value of c2 is 144.

When the equation $y = 5 x - 12$ is written in the standard form, the value of $c^{2}$ will be.

Given equation: $y = 5 x - 12$
Also, $y = 5 x - 12$ can be written as $5 x - y - 12 = 0$
So, on compairing $5 x - y - 12 = 0$ to the standard form ax + by + c = 0 we get,
a = 5
b = -1
c = -12
Now,
$c^{2}$ = $(- 12)^{2}$
$c^{2}$ = 144
Therefore, value of $c^{2}$ is 144.