Question

When the frequency of applied emf in an LCR series circuit is less than the resonant frequency,then the nature of the circuit will be:
a) Capacitive b) resistive c) inductive

• A. only a is true
• B. only a and b are true
• C. only b and c are true
• D. a, b and c are true

Answer 1

The correct option is A only a is true

$X_C=\frac{1}{\omega C}$

So, $X_C\propto \frac{1}{\omega }=\frac{1}{2\pi f}$

$X_L=\omega L$ So, $X_L\propto \omega =2\pi f$

So, as frequency decreases $X_C$ increases So, circuit becomes capacitive circuit.