When the integers $10, 0, 5, - 5, - 7$ are arranged in descending or ascending order, then find out which of the following integers always remains in the middle of the arrangement.

$0$

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$5$

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$- 7$

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$- 5$

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Solution

The correct option is A
$0$

Explanation for the correct option.
When the given integers are arranged in descending order:
$10, 5, 0, - 5, - 7$
When the given integers are arranged in ascending order:
$- 7, - 5, 0, 5, 10$
Here when the numbers are arranged in both the orders $0$ always remains in the middle of the arrangement.
Hence, the correct option is $A$ .

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Question 1

When the integers 10, 0, 5, -5, -7 are arranged in descending or ascending order, then find out which of the following integers always remains in the middle of the arrangement.

(a) 0
(b) 5
(c) -7
(d) -5

When the integers 10, 0, 5, -5, -7 are arranged in descending or ascending order, then find out which of the following integers always remains in the middle of the arrangement.

(a) 0
(b) 5
(c) -7
(d) -5

Q. When integers are arranged in descending and ascending order, find out which of the following integers always remains in the middle of the arrangement?
12, 4, 5, – 5, – 6

Q. The given rational numbers are

\frac{1}{2}, \frac{4}{- 5}, \frac{- 7}{8} .

If these numbers are arranged in the ascending order or descending order, then the middle number is:

$- 4, - 3, - 2, - 1$

These integers are arranged in ___ (ascending/descending) order.

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When the integers 10,0,5,-5,-7 are arranged in descending or ascending order, then find out which of the following integers always remains in the middle of the arrangement.

When the integers $10, 0, 5, - 5, - 7$ are arranged in descending or ascending order, then find out which of the following integers always remains in the middle of the arrangement.