When the jaws of a vernier calipers are closed, the zeroth division of its vernier scale is to the right of the zero of the main scale and the V.C.D. is 6. Find the correction to be made to the observed measurement. (take its least count as 0.1 mm)

-0.3 mm

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0.3 mm

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0.6 mm

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-0.6 mm

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Solution

The correct option is D -0.6 mm
$\begin{matrix} zero error(+ive) & = 0 + 6 \times L \cdot C = 0.6 m m correction & = (-) zero error = (-) 0.6 m m = - 0.6 m m \end{matrix}$

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When the jaws of a vernier calipers are closed, the zeroth division of its vernier scale is to the right of the zero of the main scale and the V.C.D. is 6. Find the correction to be made to the observed measurement. (take its least count as 0.1 mm)

The correct option is D -0.6 mm zero error(+ive) =0+6×L⋅C =0.6 mm correction =(−) zero error =(−)0.6 mm=−0.6 mm

The correct option is D -0.6 mm
$\begin{matrix} zero error(+ive) & = 0 + 6 \times L \cdot C = 0.6 m m correction & = (-) zero error = (-) 0.6 m m = - 0.6 m m \end{matrix}$