Question

When the kinetic energy of a body is increased by $100\%$ the momentum of the body is increased by

• A. $300\%$
• B. $41\%$
• C. $51\%$
• D. $69\%$

Answer 1

Answer: (A)

$300\%$

$K{E}_o=\frac{p^2}{2m}\left[\begin{array}{c}p=momentum\\ m=mass\end{array}\right]$

Momentum is increased by $100\%$

$K.E^{\prime }=\frac{{\left(2p\right)}^2}{2m}=\frac{4p^2}{2m}$

$\%$ increased in momentum

$=\frac{\frac{4p^2}{2m}-\frac{p^2}{2m}}{\frac{p^2}{2m}}\times 100$

$\%incrementP=300\%$