MyQuestionIcon

6

You visited us 6 times! Enjoying our articles? Unlock Full Access!

Faraday's Law

When the loop...

Question

When the loop becomes perpendicular to the magnetic field, no current flows through it momentarily as the brush loses contact with the split rings. Then why doesn't the motor stop in this position? IS IT DUE TO THE MOMENTUM PRESENT IN THE LOOP??

Open in App

Solution

Yes due to moment of ineria rotor doesnot stop continues rotates about its axis.

Suggest Corrections

thumbs-up

0

Similar questions

Q. A closed planar wire loop of area

A

and arbitrary shape is placed in a uniform magnetic field of magnitude

B

, with its plane perpendicular to the magnetic field. The resistance of the wire loop is

R

. The loop is now turned upside down by

180^{o}

so that its plane again becomes perpendicular to the magnetic field. The total charge that must have flowed through the wire ring in the process is:

Q. The given figure shows planar loops of different shapes moving out of or into a region of a magnetic field, which is directed normal to the plane of the loop away from the reader. Then the direction of induced current in each loop using Lenz's law will be

a). The magnetic flux through the rectangular loop abcd increases, due to the motion of the loop into the region of magnetic field. The induced current must flow along the path bcdab so that it opposes the increasing flux.

b) Due to the outward motion, magnetic flux through the triangular loop abc decreases due to which the induced current flows along bacb,
so as to oppose the change in flux.

c) As the magnetic flux decreases, due to motion of the irregular shaped loop abcd out of the region of magnetic field, the induced current flows
along cdabc, so as to oppose change in flux.

Note that there are no induced current as long as the loops are completely inside or outside the region of the magnetic field.
The correct statements are

Q. Figure shows a closed loop

A O C B A

in which current

I

is flowing as shown. Given

O A = O B = O C = a

. Find the magnetic field at point

B

due to this loop.

Q. Assertion :A current carrying loop is placed in uniform magnetic field as shown in figure.Torque in the loop in this case is zero. Reason: Magnetic moment vector of the loop is perpendicular to paper inwards.

Assertion :

A rectangular current loop is in an arbitrary orientation in an external uniform magnetic field. No work is required to rotate the loop about an axis perpendicular to its plane.

Reason :

All positions represent the same level of energy.

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Paradox Dragons

PHYSICS

Watch in App

explore_more_icon

Explore more

Standard X Physics

Join BYJU'S Learning Program

CrossIcon