When the mass and velocity of the body are doubled, what happens to its kinetic energy.

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Solution

Kinetic energy, $K = \frac{1}{2} m v^{2}$
When mass $m$ and velocity $v$ are doubled, the kinetic energy becomes, $K^{'} = \frac{1}{2} (2 m) (2 v)^{2} = 8 K$
Thus, kinetic energy will be eight times increasing.

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When the mass and velocity of the body are doubled, what happens to its kinetic energy.

Kinetic energy, K=12mv2When mass m and velocity v are doubled, the kinetic energy becomes, K′=12(2m)(2v)2=8KThus, kinetic energy will be eight times increasing.

Kinetic energy, $K = \frac{1}{2} m v^{2}$
When mass $m$ and velocity $v$ are doubled, the kinetic energy becomes, $K^{'} = \frac{1}{2} (2 m) (2 v)^{2} = 8 K$
Thus, kinetic energy will be eight times increasing.