When the mass of an electron becomes equal to thrice its rest mass, its speed is

\frac{2 \sqrt{2}}{3} c

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\frac{2}{3} c

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\frac{1}{3} c

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\frac{1}{4} c

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Solution

The correct option is C $\frac{2 \sqrt{2}}{3} c$
The mass of a moving body $m$ is given by special theory of relativity is given by:
$m = \frac{m_{0}}{\sqrt{1 - \frac{v^{2}}{c^{2}}}}$ ,
where, $m_{0}$ is the rest mass of the body.
According to the question, the mass of an electron becomes equal to thrice its rest mass,
So, $m = 3 m_{0}$ .
Using this, the speed of the moving body will be: $v = \frac{2 \sqrt{2}}{3} c$

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