When the mass of body is halved and velocity is doubled, then the kinetic energy of the body

remains same

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is doubled

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is 4 times

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\frac{1}{4}

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Solution

The correct option is C is doubled
$K . E = \frac{1}{2} m v^{2}$

$N e w K . E = \frac{1}{2} (\frac{m}{2}) (2 v)^{2}$ = $2 \times \frac{1}{2} m v^{2}$ = $2 \times K . E$

Hence, kinetic energy of body is doubled.

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When the mass of body is halved and velocity is doubled, then the kinetic energy of the body

The correct option is C is doubledK.E=12mv2New K.E=12(m2) (2v)2 = 2×12mv2 = 2×K.EHence, kinetic energy of body is doubled.

The correct option is C is doubled
$K . E = \frac{1}{2} m v^{2}$

$N e w K . E = \frac{1}{2} (\frac{m}{2}) (2 v)^{2}$ = $2 \times \frac{1}{2} m v^{2}$ = $2 \times K . E$

Hence, kinetic energy of body is doubled.