Question

When the momentum of a body is increased by 100%, its kinetic energy increases by

• A. 400%
• B. 100%
• C. 300%
• D. 150%

Answer 1

The correct option is C 300%

Initial kinetic energy,
$K_1=\frac{{p_1}^2}{2m}$
Final kinetic energy,
$K_2=\frac{{\left(2p_1\right)}^2}{2m}=\frac{4p_1^2}{2m}\frac{△K}{K_1}=\frac{\frac{4p_1^2}{2m}-\frac{p_1^2}{2m}}{\frac{p_1^2}{2m}}=3$