When the number $N = 0.735 ¯ ¯¯¯¯ ¯ 45$ is written as a fraction in its lowest terms, the denominator exceeds the numerator by

199

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291

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109

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219

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Solution

The correct option is B $291$
$N = 0.735 ¯ ¯¯¯¯ ¯ 45 = \frac{73545 - 735}{99000} = \frac{72810}{99000} = \frac{809}{1100}$
$∴$ Required difference $= 1100 - 809 = 291$

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When the number N=0.735¯¯¯¯¯¯45 is written as a fraction in its lowest terms, the denominator exceeds the numerator by

The correct option is B 291N=0.735¯¯¯¯¯¯45=73545−73599000=7281099000=8091100∴ Required difference =1100−809=291

When the number $N = 0.735 ¯ ¯¯¯¯ ¯ 45$ is written as a fraction in its lowest terms, the denominator exceeds the numerator by

The correct option is B $291$
$N = 0.735 ¯ ¯¯¯¯ ¯ 45 = \frac{73545 - 735}{99000} = \frac{72810}{99000} = \frac{809}{1100}$
$∴$ Required difference $= 1100 - 809 = 291$