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Mutual Induction

When the numb...

Question

When the number of turns in the two circular coils closely wound are doubled (in both), their mutual inductance becomes

A

four times

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B

two times

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C

remains same

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D

sixteen times

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Solution

The correct option is B four times
$M \propto N_{1} N_{2}$
so if both $N_{1} N_{2}$ are doubled,
$M^{'} = 4 M$

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