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Question

When the polynomial 5x3+mx+n is divided by x2+x+1 the remainder is 0. The value of (m+n) is equal to (where m,nR)

A
3
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B
5
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C
5
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D
15
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Solution

The correct option is C 5
ω and ω2 are roots of x2+x+1=0
So they are roos of 5x3+Mx+N=0 also
third root must be 1 as sum of roots is zero and 1+ω+ω2=0
So the equation is 5(x1)(xω)(xω2=5(x31)=0
M=0N=5

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