When the polynomial 5x3+mx+n is divided by x2+x+1 the remainder is 0. The value of (m+n) is equal to (where m,n∈R)
A
−3
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B
5
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C
−5
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D
15
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Solution
The correct option is C−5 ω and ω2 are roots of x2+x+1=0 So they are roos of 5x3+Mx+N=0 also third root must be 1 as sum of roots is zero and 1+ω+ω2=0 So the equation is 5(x−1)(x−ω)(x−ω2=5(x3−1)=0 ⟹M=0N=−5