When the polynomial $x^{6} - 2 x^{5} + 3 x^{2} + 4$ is divided by $x + 1$ the remainder is :

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 10
For finding the remainder, we need to use remainder theorom
let $p (x) = x^{6} - 2 x^{5} + 3 x^{2} + 4$
Hence, to find the remainder on dividing by $x + 1$ , we need to equate it to 0 and put that value of x in p(x).
$x + 1 = 0$
$\Rightarrow x = - 1$
$p (- 1) = r e m a i n d e r = (- 1)^{6} - 2 {(- 1)}^{5} + 3 {(- 1)}^{2} + 4$
$p (- 1) = 10$

Suggest Corrections

Similar questions

Q. Find the remainder by using remainder theorem when polynomial

x^{3} - 3 x^{2} + x + 1

is divided by

x - 1

Q. The remainder when the polynomial

1 + x^{2} + x^{4} + x^{6} + x . . . . . + x^{22}

is divided by

1 + x + x^{2} + x^{3} + . . . . + x^{11}

is:

The polynomial x⁴- 2x³+ 3x²- ax + b when divided by x +1 and x -1 give remainder 19 and 5 respectively . Find the remainder when the polynomial is divided by x -3

Find the remainder when the polynomial $x^{3} + 3 x^{2} + 3 x + 1$ is divided by
$(x - \frac{1}{2})$ .

Q. Find the remainder polynomial when the cubic polynomial

x^{3} - 3 x^{2} + 4 x + 5

is divided by

x - 2

Join BYJU'S Learning Program

When the polynomial x6−2x5+3x2+4 is divided by x+1 the remainder is :

The correct option is B 10For finding the remainder, we need to use remainder theoromlet p(x)=x6−2x5+3x2+4x3−2x2+x+1Hence, to find the remainder on dividing by x+1, we need to equate it to 0 and put that value of x in p(x).x+1=0⇒x=−1p(−1)=remainder=(−1)6−2(−1)5+3(−1)2+4p(−1)=10

When the polynomial $x^{6} - 2 x^{5} + 3 x^{2} + 4$ is divided by $x + 1$ the remainder is :