When the pressure of 2 litres of $O_{2}$ gas is doubled and its temperature is also doubled from 300K to 600K, the final volume of the gas is

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Solution

The correct option is D
2 lit

$\frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2} V_{2}}{T_{2}}$

$\frac{P_{1} \times 2}{300} = \frac{2 P_{1} \times V_{2}}{600}$

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