Question

When the protons of energy $h\upsilon$ fall on a photosensitive metallic surface of work function $h{\upsilon }_0$, electrons are emitted from the surface. The most energetic electron coming out of the surface have kinetic energy equal to the

• A. $h\upsilon$
• B. $h{\upsilon }_0$
• C. $h\upsilon +h{\upsilon }_0$
• D. $h\upsilon -h{\upsilon }_0$

Answer 1

The correct option is D $h\upsilon -h{\upsilon }_0$

Maximum kinetic energy of emitted photoelectrons = $h\upsilon -h{\upsilon }_0$