When the radius of the circular current carrying coil is doubled and the current in it is halved,then magnetic dipole moment of the coil originally four units becomes
A
4 units
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B
8 units
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C
16 units
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D
32 units
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Solution
The correct option is B 8 units Answer is B.
Magnetic dipole moment M with the circular current loop carrying a current I and of area A is given as follows. The magnitude of m is |m| = I A or m = I A The direction of the magnetic dipole moment is perpendicular to the plane of the loop. Thus, when the radius of the circular current carrying coil is doubled and the current in it is halved,then magnetic dipole moment of the coil originally four units is doubled. That is, 8 units.