When the repeating decimal 0.45454545... is written in the simplest fractional form, the sum of the numerator and denominator is
A
5
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B
11
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C
55
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D
16
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Solution
The correct option is D 16 n=0.45454545 100n=45.45454545 Now subtract 100n−1n=45.45454545−0.45454545 99n=45 n=4599=511 Sum of numerator and denominator =5+11=16