Question

When the road is dry and coefficient of friction is $\mu$, the maximum speed of a car in a circular path is $10$ $m{s}^{-1}$. If the road becomes wet and coefficient of friction become $\frac{\mu }{2}$, what is the maximum speed permitted?

Answer 1

$v=\sqrt{\mu rg}$

$\frac{v_2}{v_1}=\sqrt{\frac{{\mu }_2}{{\mu }_1}}$

$v_2=10\times \sqrt{\frac{\frac{\mu }{2}}{\mu }}$

$v_2=10/\sqrt{2}ms$