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Using Lenz's Law

When the rod ...

Question

When the rod is in equilibrium and makes an angle of ${53.0}^{o}$ with the floor,is the spring stretched or compressed?

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Solution

Magnetic torque on rod will come out to be clockwise. Therefore, torque of spring force should be anticlockwise or spring should be stretched.

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Similar questions

Q. A thin, uniform rod with negligible mass and length

0.200 m

is attached to the floor by a frictionless hinge at point

P (

as shown in fig

)

. A horizontal spring with force constant

k = 4.80 N m^{- 1}

connects the other end of the rod to a vertical wall. The rod is in a uniform magnetic field

B = 0.340 T

directed into the plane of the figure. There is current

I = 6.50 A

in the rod, in the direction shown. When the rod is in equilibrium and makes an angle of

{53.0}^{o}

with the floor, is the spring stretched or compressed?

Q. Assertion :A spring has potential energy, both when it is compressed or stretched. Reason: In compressing or stretching, work is done on the spring against the restoring force.

Q. ................... is the force exerted or compressed or stretched spring upon any object

Q. A thin, uniform rod with negligible mass and length

0.200 m

is attached to the floor by a frictionless hinge at point

P

(

as shown in the figure

)

. A horizontal spring with force constant

k = 4.80 {Nm}^{- 1}

connects the other end of the rod to a vertical wall. The rod is in a uniform magnetic field

B = 0.340 T

directed into the plane of the figure. There is current

I = 6.50 A

in the rod, in the direction shown.

When the rod is in equilibrium and makes an angle of

53^{\circ}

with the floor then spring length changes by -

Q. Assertion :Graph between potential energy of a spring versus the extension or compression of the spring is a straight line Reason: Potential energy of a stretched or compressed spring is proportional to square of extension or compression

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