When the signal amplitude is $1.5$ times the carrier wave amplitude, then the percent of modulation is

50 %

No worries! We‘ve got your back. Try BYJU‘S free classes today!

100 %

No worries! We‘ve got your back. Try BYJU‘S free classes today!

150 %

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

75 %

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $150 %$
Modulation index = amplitude of audio signals/amplitude of carrier wave = $(1.5 / 1) \times 100$ = $150 %$ .

Suggest Corrections

Similar questions

12 V

50

v_{m} = 20 sin 2 π (1500 t)

v_{c} = 80 sin 2 π (100, 000 t)

25 sin 2 π (2000 t)

60 sin 2 π (100, 000 t)

Join BYJU'S Learning Program