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Question

When the speed of a car is u, the minimum distance over which it can be stopped is s. If the speed becomes nu, what will be the minimum distance over which it can be stopped during same time? Assume the acceleration is constant and same in both cases.

A
sn
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B
n
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C
sn2
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D
n2s
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Solution

The correct option is D n2s
For 1st case:
Using 3rd equation of kinematics,
v2u2=2as
Here, v=0 and a=ve
0u2=2as
a=u22s

In 2nd case:
unu
v0
and a= constant
02(nu)2=2as
n2u2=2(u22s)s
s=n2s

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