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Question

When the speed of a car is v, the minimum distance over which it can be stopped is s. If the speed becomes nv, what will be the minimum distance over which it can be stopped during same retardation

A
s/n
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B
ns
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C
s/n2
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D
n2s
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Solution

The correct option is B n2s
Using, v2=u2+2as or v2u2=2as
Maximum retardation, a=v2/2s
When the initial velocity is nv, then the distance over which it can be stopped is given by
sn=u022a=(nv)22(v2/2s)=n2s

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