CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
Question

When the speed of a satellite near the surface of the earth is increased by x%, it will escape from its orbit, the value of x is:

A
11.2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
41.4
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
27.5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
34.4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 41.4
For a satellite near Earth's surface, the orbital velocity:
v0=GMeRe...(1) And escape velocity:
ve=2GMeRe...(2) From equation (1) and (2),

ve=2v0

Satellite will escape from earth's surface if v0 is increased to ve.

So, percentage increase in v0,

x%=vev0v0×100

x%=(2v0v0v0)×100

x%=41.4%

Hence, option (b) is the correct answer.

flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon