When the sun rays are incident at an angle of 600 then intensity is I. What will be the intensity if the sun rays are incident at 30o?
A
I√3
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B
√3I
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C
3I
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D
I3
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Solution
The correct option is B√3I The intensity of sun rays that making angle θ is equal to I0cosθ, where I0 is the intensity of the sun rays if it incident perpendicularly to the surface.
Now, when the rays making angle 30∘, intensity will be I(cos30/cos60)=√3I