Question

When the switch is closed, the initial current through the $1\Omega$ resistor is :

• A. 2 A
• B. 4 A
• C. 3 A
• D. 6 A

Answer 1

The correct option is B 4 A

At $t=0$, the capacitor will behave like a short circuit. So the resistors 6 and 3 become in parallel.
The equivalent resistance is $R_{eq}=\frac{6\times 3}{6+3}=2\Omega$
Now current through $1\Omega$ resistance is $i=\frac{12}{1+2}=4A$