When the temperature of a gas is raised from 27∘C to 90∘C, the percentage increase in the r.m.s. velocity of the molecules will be
vmax = √3RTM ⇒ v2v1 = √T2T2 = √(273+90)(273+90) = 1.1 % increase = (v2v1−1) × 100 = 0.1 × 100 = 10%
When the temperature of a gas is raised from 27∘ C to 90∘ C, the percentage increase in the r.m.s. velocity of the molecules will be